12.04 volts indicates the battery did not take a charge. When that happens to me it is almost always due to one of the cable clamps didn't make a good connection.
When the battery is this discharged, watch the meter on your portable charger. It typically takes a good 15 minutes before the battery starts to take a charge. It takes that long for the acid to fill with electrons and become conductive. When that happens, you'll see the amp meter stay near "0" at first, then, after ten to 15 minutes, the current will go up. We'd like it to not go higher than ten amps. A little more for newer batteries is okay, but home chargers put out a "rectified sine wave" which will vibrate the battery's plates. The higher the charging current, the harder the plates vibrate. As all batteries age, the lead flakes off the plates and collects in the bottom of the case. Charging at higher rates hastens how fast that flaking occurs. That usually won't destroy a battery, but it will decrease the amount of time before the flaked-off lead builds up high enough to short one of the cells. Alternators put out three-phase current. That is more efficient and very much smoother, so vibrating battery plates isn't a concern.
Also check if your battery is of the newer "absorbed glass mat", (AGM) design. I've gotten conflicting information as to the advantages, disadvantages, and proper care for these batteries. My 2014 Ram came with one. The truck sat unused over a winter, so I assumed the battery was drained and froze. When I bought a new one from my trusted battery store, they refused to take the old one for the core until I tried charging it at a slow rate for three days. To my surprise, it did recover and is working fine in another vehicle, but it did take a long time to recharge.
I know you don't need this, but for the benefit of others researching this topic, here's a link to an article on charging batteries:
https://www.2carpros.com/articles/how-to-charge-your-car-battery
After rereading your last reply, it occurs to me the voltages you listed might all be with the engine running. If that's the case, forget what I just posted about the battery not being charged. Its voltage is going to be drawn down when supplying the current to run the engine and other circuits. This is where we have to look at the charging system.
I started to mention this in my first reply, but I didn't go far enough. All "AC generators" have diodes inside to turn their alternating current into direct current that can be stored in a battery. As a point of interest, Chrysler developed the AC generator for their 1960 models, and copyrighted the term, "alternator". This first diagram is of your charging system. The second one is just expanded to make the important area easier to read. My orange arrow is pointing to one of the diodes. All alternators have six. The extra two here were added to squeeze out a little extra output current capacity. Some designs even have 12 diodes; basically two alternators in one package, for twice the output current.
Diodes are one-way valves for electrical current flow. For automotive discussion, current can flow in the direction the arrow-part of the symbol is pointing, in this case from left to right. When the engine is running, current flows through the diodes, out the output terminal, (red arrow), through the black / gray wire, splice S101, then through the dark green fuse link wire, "A11 10 DG". "A" circuits originate at the battery positive post. This is number 11 of those circuits. The "10" means it's a 10-gauge fuse wire, and the "DG" is for "dark green" The color denotes the current rating, just like it does with regular fuses.
When the engine is stopped, the battery would like to discharge through the alternator, but it's the diodes that prevent that from happening. Now they're "reverse-biased", meaning they block current flow. That is, until the battery cables or jumper cables are reversed. Doing that in effect turns the diodes around, so now they act like a dead short. There's nothing to limit current flow, so eventually the fuse link wire burns open.
If I haven't confused you yet, I'd like to add a comment here that has stumped even very experienced electrical specialists. When the charging system is working normally, you will find full battery voltage, (12.6 volts), on the alternator's output stud, when the engine is off.
That 12 volts will be there all the time. It will rise to between 13.75 and 14.75 volts when the engine is running. To identify if the fuse link is burned open, that one simple voltage test should be all that's needed. Now you'll find 0 volts with the engine off. A test light is accurate enough for this, (and in this case, more accurate), but a lot of professionals use digital voltmeters. This is a perfect example of where the expensive meter gives false readings.
When fuse link wires burn open, they deposit a carbon track on the inside of the insulation where the arcing occurred. That's the same carbon track that used to occur inside distributor caps and short out the high voltage to some spark plugs. Digital voltmeters work by measuring electrical pressure, (voltage), but they don't require much current flow through the circuit to do that. Enough of a tiny tickle can get through the carbon track for the meter to falsely detect the 12 volts. This is where a lot of experts incorrectly think that circuit must be okay. Instead, if you use an old-fashioned, inexpensive test light, it will not light up. They require current to flow through them to give their indications. That much current can't get through the carbon track, so the test light accurately shows there's no 12 volts on the alternator's output stud.
The point of this sad story is use a test light to check for voltage on the alternator's output stud. If you really do have 12 volts there, check it again with the engine running. If it doesn't jump up to at least 13.5 volts, we'll need to continue with the next steps. That will be to measure the two voltages on the two smaller terminals on the back of the alternator, (blue and green arrows). Those must be taken with the engine running.
If you do find 0 volts on the output stud, as I suspect, it's the fuse link wire that must be checked. Previous discussion, as I recall, indicated you may have three fuse links that tap off the starter. That's just a convenient tie point so they didn't have to run multiple wires all the way back to the battery. Tug gently on those wires. If one acts like a rubber band, that one is burned open.
You can make a temporary repair to a fuse link wire by cutting it by the break, stripping some insulation from each end, then twisting the ends together. The circuit is still protected as long as part of that wire is still there. The wire itself is just a regular wire, but it's a smaller diameter than the wires it protects. That makes it the weak link in the chain.
The proper repair is to buy a new fuse link from an auto parts store. They are usually about 12" long which is enough to cut and make two or three repairs. They'll have a dull color denoting the current rating, and that insulation will not melt or burn. Don't use regular wire for this purpose as its insulation can burn and start a fire.
Twist the ends of the new piece to the ends left behind when you cut the old piece out. Before you twist the last ends together, slide on two pieces of moisture-proof heat-shrink tubing. That tubing is going to sit over the wires that are twisted together. That makes them a much larger diameter, and therefore, not part of the weak link in the chain. The wire won't burn open along those splices, so there's no worry about the heat-shrink tubing catching on fire. Even if that was a concern, the event is over too quickly to get the heat-shrink tubing warm.
I could go into even more detail, but I'll wait to hear what you find up to this point.
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Saturday, April 2nd, 2022 AT 5:36 PM